3c^2+5c-12=0

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Solution for 3c^2+5c-12=0 equation:


Simplifying
3c2 + 5c + -12 = 0

Reorder the terms:
-12 + 5c + 3c2 = 0

Solving
-12 + 5c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -1c)(4 + -3c) = 0

Subproblem 1

Set the factor '(-3 + -1c)' equal to zero and attempt to solve: Simplifying -3 + -1c = 0 Solving -3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1c = 0 + 3 -1c = 0 + 3 Combine like terms: 0 + 3 = 3 -1c = 3 Divide each side by '-1'. c = -3 Simplifying c = -3

Subproblem 2

Set the factor '(4 + -3c)' equal to zero and attempt to solve: Simplifying 4 + -3c = 0 Solving 4 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -3c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -3c = 0 + -4 -3c = 0 + -4 Combine like terms: 0 + -4 = -4 -3c = -4 Divide each side by '-3'. c = 1.333333333 Simplifying c = 1.333333333

Solution

c = {-3, 1.333333333}

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